x^2=0.01-x

Solution for x^2=0.01-x equation:

x^2=0.01-x

We move all terms to the left:

x^2-(0.01-x)=0

We add all the numbers together, and all the variables

x^2-(-1x+0.01)=0

We get rid of parentheses

x^2+1x-0.01=0

We add all the numbers together, and all the variables

x^2+x-0.01=0

a = 1; b = 1; c = -0.01;
Δ = b2-4ac
Δ = 12-4·1·(-0.01)
Δ = 1.04
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{1.04}}{2*1}=\frac{-1-\sqrt{1.04}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{1.04}}{2*1}=\frac{-1+\sqrt{1.04}}{2}
$